{ "lane": "full_recipe", "model": "qwen3.8-flash-next", "thinking": "off", "concurrency": 1, "n": 40, "summary": { "coding": { "n": 5, "auto_score": 1.0, "ttft_med_s": 0.24, "decode_med_tok_s": 44.5, "tokens_med": 138 }, "reasoning": { "n": 5, "auto_score": 1.0, "ttft_med_s": 0.27, "decode_med_tok_s": 46.6, "tokens_med": 423 }, "json": { "n": 5, "auto_score": 1.0, "ttft_med_s": 0.29, "decode_med_tok_s": 47.1, "tokens_med": 38 }, "html": { "n": 5, "auto_score": 1.0, "ttft_med_s": 0.27, "decode_med_tok_s": 48.2, "tokens_med": 163 }, "prose": { "n": 5, "auto_score": 0.6, "ttft_med_s": 0.26, "decode_med_tok_s": 29.4, "tokens_med": 194 }, "narrative": { "n": 5, "auto_score": 0.693, "ttft_med_s": 0.26, "decode_med_tok_s": 28.9, "tokens_med": 337 }, "summary": { "n": 5, "auto_score": 0.75, "ttft_med_s": 0.23, "decode_med_tok_s": 36.0, "tokens_med": 31 }, "format": { "n": 5, "auto_score": 1.0, "ttft_med_s": 0.25, "decode_med_tok_s": 31.2, "tokens_med": 21 } }, "batches": [], "overall": { "auto_score": 0.88, "ttft_med_s": 0.26, "decode_med_tok_s": 43.5, "agg_tok_s_med": null }, "items": [ { "ttft_s": 0.22, "wall_s": 3.3, "completion_tokens": 138, "prompt_tokens": 47, "decode_tok_s": 44.5, "reasoning_chars": 0, "finish": "stop", "output": "```python\ndef merge_intervals(intervals):\n if not intervals:\n return []\n \n # Sort intervals by start time\n intervals.sort(key=lambda x: x[0])\n \n merged = [intervals[0]]\n \n for current in intervals[1:]:\n last = merged[-1]\n # If current interval overlaps with the last merged interval\n if current[0] <= last[1]:\n # Merge them by updating the end time\n last[1] = max(last[1], current[1])\n else:\n merged.append(current)\n \n return merged\n```", "id": "code1", "category": "coding", "prompt": "Write a Python function merge_intervals(intervals) that merges overlapping [start, end] intervals and returns the merged list sorted by start. Return only one ```python code block.", "score": 1.0, "fails": [] }, { "ttft_s": 0.27, "wall_s": 5.97, "completion_tokens": 253, "prompt_tokens": 82, "decode_tok_s": 44.2, "reasoning_chars": 0, "finish": "stop", "output": "```python\ndef parse_duration(s: str) -> int:\n \"\"\"\n Convert a duration string like '1h30m15s', '45s', '2h', '3m', '1h1s'\n into total seconds (int). Units appear in h, m, s order and may be omitted.\n \"\"\"\n total_seconds = 0\n current_number = \"\"\n \n for char in s:\n if char.isdigit():\n current_number += char\n elif char == 'h':\n if current_number:\n total_seconds += int(current_number) * 3600\n current_number = \"\"\n elif char == 'm':\n if current_number:\n total_seconds += int(current_number) * 60\n current_number = \"\"\n elif char == 's':\n if current_number:\n total_seconds += int(current_number)\n current_number = \"\"\n \n # Handle any remaining number (shouldn't happen with valid input, but just in case)\n if current_number:\n total_seconds += int(current_number)\n \n return total_seconds\n```", "id": "code2", "category": "coding", "prompt": "Write a Python function parse_duration(s) that converts strings like '1h30m15s', '45s', '2h', '3m', '1h1s' into total seconds (int). Units may be omitted but always appear in h, m, s order. Return only one ```python code block.", "score": 1.0, "fails": [] }, { "ttft_s": 0.24, "wall_s": 2.11, "completion_tokens": 85, "prompt_tokens": 48, "decode_tok_s": 45.1, "reasoning_chars": 0, "finish": "stop", "output": "```python\ndef top_k_frequent(words, k):\n from collections import Counter\n \n # Count frequencies\n freq = Counter(words)\n \n # Sort by frequency descending, then by word ascending (alphabetically)\n sorted_words = sorted(freq.keys(), key=lambda w: (-freq[w], w))\n \n # Return the top k\n return sorted_words[:k]\n```", "id": "code3", "category": "coding", "prompt": "Write a Python function top_k_frequent(words, k) returning the k most frequent words, most frequent first; ties broken alphabetically. Return only one ```python code block.", "score": 1.0, "fails": [] }, { "ttft_s": 0.31, "wall_s": 2.3, "completion_tokens": 88, "prompt_tokens": 123, "decode_tok_s": 43.7, "reasoning_chars": 0, "finish": "stop", "output": "```python\ndef binary_search(a, target):\n lo, hi = 0, len(a)\n while lo < hi:\n mid = (lo + hi) // 2\n if a[mid] == target:\n return mid\n if a[mid] < target:\n lo = mid + 1\n else:\n hi = mid\n return -1\n```", "id": "code4", "category": "coding", "prompt": "This binary search has a bug that can make it loop forever. Return the corrected function only, as one ```python code block, same name and signature.\n\ndef binary_search(a, target):\n lo, hi = 0, len(a)\n while lo < hi:\n mid = (lo + hi) // 2\n if a[mid] == target:\n return mid\n if a[mid] < target:\n lo = mid\n else:\n hi = mid\n return -1", "score": 1.0, "fails": [] }, { "ttft_s": 0.23, "wall_s": 3.42, "completion_tokens": 152, "prompt_tokens": 38, "decode_tok_s": 47.3, "reasoning_chars": 0, "finish": "stop", "output": "```python\ndef roman_to_int(s: str) -> int:\n roman_values = {\n 'I': 1,\n 'V': 5,\n 'X': 10,\n 'L': 50,\n 'C': 100,\n 'D': 500,\n 'M': 1000\n }\n \n total = 0\n prev_value = 0\n \n for char in reversed(s):\n value = roman_values[char]\n if value < prev_value:\n total -= value\n else:\n total += value\n prev_value = value\n \n return total\n```", "id": "code5", "category": "coding", "prompt": "Write a Python function roman_to_int(s) converting a Roman numeral string to an integer. Return only one ```python code block.", "score": 1.0, "fails": [] }, { "ttft_s": 0.25, "wall_s": 8.38, "completion_tokens": 380, "prompt_tokens": 60, "decode_tok_s": 46.6, "reasoning_chars": 0, "finish": "stop", "output": "Let $A$ be Ana's current age and $B$ be Ben's current age.\n\nFrom the first statement, \"Ana is twice as old as Ben,\" we can write the equation:\n$$ A = 2B $$\n\nFrom the second statement, \"In 6 years Ana will be 1.5 times Ben's age,\" we can write the equation:\n$$ A + 6 = 1.5(B + 6) $$\n\nNow, substitute the value of $A$ from the first equation into the second equation:\n$$ 2B + 6 = 1.5(B + 6) $$\n\nExpand the right side of the equation:\n$$ 2B + 6 = 1.5B + 9 $$\n\nSubtract $1.5B$ from both sides to group the terms with $B$:\n$$ 2B - 1.5B + 6 = 9 $$\n$$ 0.5B + 6 = 9 $$\n\nSubtract 6 from both sides:\n$$ 0.5B = 3 $$\n\nMultiply both sides by 2 to solve for $B$:\n$$ B = 6 $$\n\nSo, Ben is currently 6 years old.\n\nLet's verify the answer:\n- If Ben is 6, Ana is $2 \\times 6 = 12$.\n- In 6 years, Ben will be $6 + 6 = 12$.\n- In 6 years, Ana will be $12 + 6 = 18$.\n- Is 18 equal to 1.5 times 12?\n $$ 1.5 \\times 12 = 18 $$\n Yes, the condition holds.\n\nANSWER: 6", "id": "reason1", "category": "reasoning", "prompt": "Ana is twice as old as Ben. In 6 years Ana will be 1.5 times Ben's age. How old is Ben now?\n\nGive your final answer on the last line exactly as: ANSWER: ", "score": 1.0, "fails": [] }, { "ttft_s": 0.27, "wall_s": 9.07, "completion_tokens": 423, "prompt_tokens": 56, "decode_tok_s": 48.0, "reasoning_chars": 0, "finish": "stop", "output": "To find the probability of getting exactly 2 heads when flipping a fair coin 4 times, we can follow these steps:\n\n1. **Determine the total number of possible outcomes:**\n Since each coin flip has 2 possible outcomes (Heads or Tails) and there are 4 independent flips, the total number of outcomes is:\n $$2^4 = 16$$\n\n2. **Determine the number of favorable outcomes:**\n We need to find the number of ways to get exactly 2 heads in 4 flips. This is a combination problem where we choose 2 positions for the heads out of the 4 available positions. The formula for combinations is $\\binom{n}{k} = \\frac{n!}{k!(n-k)!}$.\n Here, $n=4$ and $k=2$:\n $$\\binom{4}{2} = \\frac{4!}{2!(4-2)!} = \\frac{4 \\times 3 \\times 2 \\times 1}{(2 \\times 1)(2 \\times 1)} = \\frac{24}{4} = 6$$\n So, there are 6 favorable outcomes: HHTT, HTHT, HTTH, THHT, THTH, TTHH.\n\n3. **Calculate the probability:**\n The probability $P$ is the ratio of favorable outcomes to total outcomes:\n $$P = \\frac{\\text{Number of favorable outcomes}}{\\text{Total number of outcomes}} = \\frac{6}{16}$$\n\n4. **Simplify the fraction:**\n Both 6 and 16 are divisible by 2:\n $$\\frac{6}{16} = \\frac{3}{8}$$\n The fraction $\\frac{3}{8}$ is in lowest terms because 3 and 8 share no common factors other than 1.\n\nANSWER: 3/8", "id": "reason2", "category": "reasoning", "prompt": "A fair coin is flipped 4 times. What is the probability of exactly 2 heads? Give a fraction in lowest terms.\n\nGive your final answer on the last line exactly as: ANSWER: ", "score": 1.0, "fails": [] }, { "ttft_s": 0.27, "wall_s": 8.37, "completion_tokens": 326, "prompt_tokens": 57, "decode_tok_s": 40.1, "reasoning_chars": 0, "finish": "stop", "output": "To determine who finishes third, let's analyze the relative positions of the five runners: Al, Bo, Cal, Dee, and Eve.\n\n1. **Analyze the constraints:**\n * \"Bo finishes last.\" -> Bo is in position 5.\n * \"Al finishes before Cal.\" -> Al < Cal (Al has a lower position number than Cal).\n * \"Dee finishes before Eve but after Cal.\" -> Cal < Dee < Eve.\n\n2. **Combine the constraints:**\n * From \"Al < Cal\" and \"Cal < Dee < Eve\", we can chain these together:\n Al < Cal < Dee < Eve\n * We also know Bo is last (position 5).\n\n3. **Determine the full order:**\n * The chain Al < Cal < Dee < Eve involves four runners.\n * Since Bo is in position 5, the other four runners (Al, Cal, Dee, Eve) must occupy positions 1, 2, 3, and 4.\n * Because their relative order is fixed as Al < Cal < Dee < Eve, their specific positions are determined:\n * Position 1: Al\n * Position 2: Cal\n * Position 3: Dee\n * Position 4: Eve\n * Position 5: Bo\n\n4. **Identify the third runner:**\n * The runner in position 3 is Dee.\n\nANSWER: Dee", "id": "reason3", "category": "reasoning", "prompt": "Five runners finish a race. Dee finishes before Eve but after Cal. Bo finishes last. Al finishes before Cal. Who finishes third?\n\nGive your final answer on the last line exactly as: ANSWER: ", "score": 1.0, "fails": [] }, { "ttft_s": 0.29, "wall_s": 10.14, "completion_tokens": 439, "prompt_tokens": 83, "decode_tok_s": 44.5, "reasoning_chars": 0, "finish": "stop", "output": "To solve this problem, we can avoid the complex calculation of summing an infinite series of the bird's back-and-forth trips by focusing on the total time the bird is in the air.\n\n**Step 1: Calculate the time until the trains meet.**\n\nThe two trains are traveling toward each other. Their relative speed is the sum of their individual speeds.\n* Speed of Train 1 ($v_1$) = $70$ km/h\n* Speed of Train 2 ($v_2$) = $80$ km/h\n* Relative speed ($v_{rel}$) = $v_1 + v_2 = 70 + 80 = 150$ km/h\n\nThe initial distance between the trains ($d$) is $300$ km.\n\nThe time ($t$) it takes for the trains to meet is given by:\n$$ t = \\frac{d}{v_{rel}} $$\n$$ t = \\frac{300 \\text{ km}}{150 \\text{ km/h}} $$\n$$ t = 2 \\text{ hours} $$\n\n**Step 2: Calculate the distance the bird flies.**\n\nThe bird is flying continuously from the moment the trains start until the moment they meet. Therefore, the bird is in the air for exactly the same amount of time as it takes for the trains to meet, which is $2$ hours.\n\n* Speed of the bird ($v_{bird}$) = $120$ km/h\n* Time flying ($t$) = $2$ hours\n\nThe total distance ($d_{bird}$) the bird flies is:\n$$ d_{bird} = v_{bird} \\times t $$\n$$ d_{bird} = 120 \\text{ km/h} \\times 2 \\text{ h} $$\n$$ d_{bird} = 240 \\text{ km} $$\n\n**Conclusion:**\n\nThe bird flies a total distance of 240 km.\n\nANSWER: 240", "id": "reason4", "category": "reasoning", "prompt": "Two trains 300 km apart travel toward each other at 70 km/h and 80 km/h. A bird flying at 120 km/h goes back and forth between them until they meet. How many km does the bird fly?\n\nGive your final answer on the last line exactly as: ANSWER: ", "score": 1.0, "fails": [] }, { "ttft_s": 0.25, "wall_s": 14.55, "completion_tokens": 681, "prompt_tokens": 47, "decode_tok_s": 47.5, "reasoning_chars": 0, "finish": "stop", "output": "To find the remainder when $7^{100}$ is divided by 5, we can use modular arithmetic.\n\n**Step 1: Simplify the base modulo 5**\nFirst, we look at the base, 7, modulo 5.\n$$ 7 \\equiv 2 \\pmod{5} $$\nTherefore:\n$$ 7^{100} \\equiv 2^{100} \\pmod{5} $$\n\n**Step 2: Use Fermat's Little Theorem**\nFermat's Little Theorem states that if $p$ is a prime number and $a$ is an integer not divisible by $p$, then:\n$$ a^{p-1} \\equiv 1 \\pmod{p} $$\nHere, $p = 5$ and $a = 2$. Since 5 is prime and 2 is not divisible by 5, we have:\n$$ 2^{5-1} \\equiv 1 \\pmod{5} $$\n$$ 2^4 \\equiv 1 \\pmod{5} $$\n\n**Step 3: Simplify the exponent**\nWe need to calculate $2^{100} \\pmod{5}$. We can express the exponent 100 as a multiple of 4:\n$$ 100 = 4 \\times 25 $$\nSo,\n$$ 2^{100} = (2^4)^{25} $$\nSubstituting the congruence from Step 2:\n$$ (2^4)^{25} \\equiv 1^{25} \\pmod{5} $$\n$$ 1^{25} = 1 $$\nThus,\n$$ 2^{100} \\equiv 1 \\pmod{5} $$\n\n**Alternative Method: Pattern Recognition**\nLet's look at the powers of 7 modulo 5:\n- $7^1 = 7 \\equiv 2 \\pmod{5}$\n- $7^2 = 49 \\equiv 4 \\equiv -1 \\pmod{5}$\n- $7^3 = 7^2 \\cdot 7 \\equiv -1 \\cdot 2 = -2 \\equiv 3 \\pmod{5}$\n- $7^4 = 7^3 \\cdot 7 \\equiv 3 \\cdot 2 = 6 \\equiv 1 \\pmod{5}$\n\nThe powers of 7 modulo 5 repeat in a cycle of 4: $\\{2, 4, 3, 1\\}$.\nSince the exponent is 100, and $100$ is divisible by 4 ($100 = 4 \\times 25$), the remainder corresponds to the last term in the cycle, which is 1.\n$$ 7^{100} = (7^4)^{25} \\equiv 1^{25} \\equiv 1 \\pmod{5} $$\n\n**Conclusion**\nThe remainder when $7^{100}$ is divided by 5 is 1.\n\nANSWER: 1", "id": "reason5", "category": "reasoning", "prompt": "What is the remainder when 7^100 is divided by 5?\n\nGive your final answer on the last line exactly as: ANSWER: ", "score": 1.0, "fails": [] }, { "ttft_s": 0.3, "wall_s": 1.59, "completion_tokens": 66, "prompt_tokens": 99, "decode_tok_s": 50.4, "reasoning_chars": 0, "finish": "stop", "output": "{\n \"invoice_id\": 4471,\n \"customer\": \"Marta Ruiz\",\n \"issued\": \"2026-03-14\",\n \"amount\": 1250.50,\n \"due_days\": 30\n}", "id": "json1", "category": "json", "prompt": "Extract into a JSON object with keys invoice_id (integer), customer (string), issued (ISO date string), amount (number), due_days (integer):\n\n\"Invoice 4471 was issued to Marta Ruiz on 2026-03-14 for $1,250.50, due in 30 days.\"\n\nOutput only the JSON, no prose, no code fences.", "score": 1.0, "fails": [] }, { "ttft_s": 0.26, "wall_s": 1.56, "completion_tokens": 67, "prompt_tokens": 63, "decode_tok_s": 51.0, "reasoning_chars": 0, "finish": "stop", "output": "[\n {\n \"name\": \"apple\",\n \"qty\": 3,\n \"price\": 0.5\n },\n {\n \"name\": \"pear\",\n \"qty\": 2,\n \"price\": 0.75\n }\n]", "id": "json2", "category": "json", "prompt": "Convert this CSV to a JSON array of objects with numeric qty and price:\n\nname,qty,price\napple,3,0.5\npear,2,0.75\n\nOutput only the JSON, no prose, no code fences.", "score": 1.0, "fails": [] }, { "ttft_s": 0.27, "wall_s": 0.73, "completion_tokens": 21, "prompt_tokens": 58, "decode_tok_s": 43.5, "reasoning_chars": 0, "finish": "stop", "output": "{\"user\": \"sam\", \"tags\": [\"a\", \"b\"], \"active\": true}", "id": "json3", "category": "json", "prompt": "Fix this invalid JSON and output only the corrected JSON:\n\n{'user': 'sam', 'tags': ['a', 'b',], 'active': True}\n\nOutput only the JSON, no prose, no code fences.", "score": 1.0, "fails": [] }, { "ttft_s": 0.3, "wall_s": 0.92, "completion_tokens": 30, "prompt_tokens": 86, "decode_tok_s": 47.1, "reasoning_chars": 0, "finish": "stop", "output": "{\"Oslo\": 4.0, \"Cairo\": 31.0, \"Lima\": 19.5}", "id": "json4", "category": "json", "prompt": "Return a JSON object mapping each city to the arithmetic mean of its temperatures:\n\n{\"Oslo\": [2, 4, 6], \"Cairo\": [30, 32], \"Lima\": [18, 19, 20, 21]}\n\nOutput only the JSON, no prose, no code fences.", "score": 1.0, "fails": [] }, { "ttft_s": 0.29, "wall_s": 1.14, "completion_tokens": 38, "prompt_tokens": 76, "decode_tok_s": 43.6, "reasoning_chars": 0, "finish": "stop", "output": "{\"id\": 7, \"name\": \"Widget\", \"price\": 19.99, \"in_stock\": true, \"tags\": [\"tools\", \"home\"]}", "id": "json5", "category": "json", "prompt": "Produce a JSON object with exactly these keys and values: id = integer 7, name = string \"Widget\", price = number 19.99, in_stock = boolean true, tags = array of strings [\"tools\", \"home\"].\n\nOutput only the JSON, no prose, no code fences.", "score": 1.0, "fails": [] }, { "ttft_s": 0.28, "wall_s": 15.82, "completion_tokens": 750, "prompt_tokens": 71, "decode_tok_s": 48.2, "reasoning_chars": 0, "finish": "stop", "output": "```html\n\n\n\n \n \n Spark Bench\n \n\n\n
\n

Spark Bench

\n \n
\n
\n
\n

Spark Bench is a lightweight benchmarking suite designed to measure and compare the performance of data processing pipelines across various workloads, helping developers identify bottlenecks and optimize throughput.

\n
\n
\n\n\n```", "id": "html1", "category": "html", "prompt": "Write a complete HTML5 page: a
containing an

that reads Spark Bench and a